71 lines
1.5 KiB
C
71 lines
1.5 KiB
C
// SPDX-License-Identifier: GPL-2.0-or-later
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/*
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* Copyright (c) Linux Test Project, 2020
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* Copyright (c) Wipro Technologies Ltd, 2002
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*/
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/*
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* This is a basic test for iopl(2) system call.
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*
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* Test the system call for possible privelege levels.
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* As the privelge level for a normal process is 0, start by
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* setting/changing the level to 0.
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*
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* Author: Subhab Biswas <subhabrata.biswas@wipro.com>
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*/
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#include <errno.h>
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#include <unistd.h>
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#include "tst_test.h"
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#if defined __i386__ || defined(__x86_64__)
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#include <sys/io.h>
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static void verify_iopl(void)
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{
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int total_level = 4;
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int level;
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for (level = 0; level < total_level; ++level) {
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TEST(iopl(level));
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if (TST_RET == -1) {
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tst_res(TFAIL | TTERRNO, "iopl() failed for level %d, "
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"errno=%d : %s", level,
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TST_ERR, tst_strerrno(TST_ERR));
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} else {
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tst_res(TPASS, "iopl() passed for level %d, "
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"returned %ld", level, TST_RET);
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}
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}
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}
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static void setup(void)
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{
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/* iopl() is restricted under kernel lockdown. */
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if (tst_lockdown_enabled())
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tst_brk(TCONF, "Kernel is locked down, skip this test");
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}
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static void cleanup(void)
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{
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/*
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* back to I/O privilege for normal process.
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*/
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if (iopl(0) == -1)
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tst_res(TWARN, "iopl() cleanup failed");
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}
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static struct tst_test test = {
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.test_all = verify_iopl,
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.needs_root = 1,
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.setup = setup,
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.cleanup = cleanup,
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};
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#else
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TST_TEST_TCONF("LSB v1.3 does not specify iopl() for this architecture. (only for i386 or x86_64)");
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#endif /* __i386_, __x86_64__*/
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