68 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			C
		
	
	
	
			
		
		
	
	
			68 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			C
		
	
	
	
| /*
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|  * percent.c		- Take percentage of a number
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|  *
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|  * Copyright (C) 2006  Theodore Ts'o <tytso@mit.edu>
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|  *
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|  * %Begin-Header%
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|  * This file may be redistributed under the terms of the GNU Library
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|  * General Public License, version 2.
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|  * %End-Header%
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|  */
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| 
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| #include "config.h"
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| #include "e2p.h"
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| 
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| #include <stdlib.h>
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| 
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| /*
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|  * We work really hard to calculate this accurately, while avoiding
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|  * an overflow.  "Is there a hyphen in anal-retentive?"  :-)
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|  */
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| unsigned int e2p_percent(int percent, unsigned int base)
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| {
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| 	unsigned int mask = ~((1 << (sizeof(unsigned int) - 1) * 8) - 1);
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| 
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| 	if (!percent)
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| 		return 0;
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| 	if (100 % percent == 0)
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| 		return base / (100 / percent);
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| 	if (mask & base)
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| 		return (base / 100) * percent;
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| 	return base * percent / 100;
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| }
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| 
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| #ifdef DEBUG
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| #include <unistd.h>
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| #include <stdio.h>
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| 
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| main(int argc, char **argv)
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| {
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| 	unsigned int base;
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| 	int percent;
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| 	char *p;
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| 	int log_block_size = 0;
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| 
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| 	if (argc != 3) {
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| 		fprintf(stderr, "Usage: %s percent base\n", argv[0]);
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| 		exit(1);
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| 	}
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| 
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| 	percent = strtoul(argv[1], &p, 0);
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| 	if (p[0] && p[1]) {
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| 		fprintf(stderr, "Bad percent: %s\n", argv[1]);
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| 		exit(1);
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| 	}
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| 
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| 	base = strtoul(argv[2], &p, 0);
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| 	if (p[0] && p[1]) {
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| 		fprintf(stderr, "Bad base: %s\n", argv[2]);
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| 		exit(1);
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| 	}
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| 
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| 	printf("%d percent of %u is %u.\n", percent, base,
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| 	       e2p_percent(percent, base));
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| 
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| 	exit(0);
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| }
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| #endif
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